A) \[{{C}_{2}}{{H}_{6}}\]
B) \[{{C}_{2}}{{H}_{4}}\]
C) \[BeC{{l}_{2}}\]
D) \[{{C}_{2}}{{H}_{2}}\]
Correct Answer: B
Solution :
[b] When there is\[3\sigma \]bonds, the hybridisation is \[s{{p}^{2}}\]. The structures of the given compounds are [a] [b] [c] [d] Thus,\[C{{H}_{2}}=C{{H}_{2}}\]has\[s{{p}^{2}}\]hybridisation.You need to login to perform this action.
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