A) \[\pi /12\]
B) \[\pi /6\]
C) \[\pi /4\]
D) \[\pi /3\]
Correct Answer: A
Solution :
Maximum value of\[f(x)=\sqrt{2},\]when\[x+\pi /6=\pi /4\] i.e., when \[x=\frac{\pi }{12}\]You need to login to perform this action.
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