A) \[-1\]
B) 0
C) 1
D) 13/3
Correct Answer: A
Solution :
\[\underset{x\to {{1}^{-}}}{\mathop{\lim }}\,f(x)=\underset{x\to 1}{\mathop{\lim }}\,(5x-4)=1\] \[\underset{x\to {{1}^{+}}}{\mathop{\lim }}\,f(x)=\underset{x\to 1}{\mathop{\lim }}\,(4{{x}^{2}}+3bx)=4+3b\] \[\Rightarrow \]\[4+3b=1\]\[\Rightarrow \]\[b=-1\]You need to login to perform this action.
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