A) \[{{p}^{2}}=4q\]
B) \[{{p}^{2}}=4q+1\]
C) \[{{p}^{2}}=4q-1\]
D) \[{{p}^{2}}=q\]
Correct Answer: B
Solution :
Let \[\alpha ,\alpha +1\]be the roots of the given equation, then \[\alpha +\alpha +1=-p\] \[2\alpha =-p-1\] \[\Rightarrow \] \[\alpha =-\frac{p+1}{2}\] Also, \[a(a+1)=q\] \[\Rightarrow \] \[-1+{{p}^{2}}=4q\] \[\Rightarrow \] \[{{p}^{2}}=4q+1\]
You need to login to perform this action.
You will be redirected in
3 sec
