A) 8.5 kN
B) 7.5 kN
C) 6.5 kN
D) 30 kN
Correct Answer: B
Solution :
From work-energy theorem Work done by resistance of block = change in KE \[{{F}_{x}}=\frac{1}{2}m({{v}^{2}}-{{u}^{2}})\] \[F=\frac{0.05\times [{{(800)}^{2}}-{{(200)}^{2}}]}{2\times 2}\] \[F=7500N\] \[F=7.5kN\]You need to login to perform this action.
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