A) 3.5 min
B) 14 min
C) 7 min
D) 10 min
Correct Answer: C
Solution :
Rate of cooling \[\frac{dQ}{dt}\propto \]temperature difference Ist case \[\frac{60-40}{7}=k(60-10)\] \[k=\frac{2}{35}\] IInd case \[\frac{40-28}{t}=k(40-10)\] \[t=7\text{ }\min \]You need to login to perform this action.
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