A) \[1/y+3/x=1\]
B) \[x+3y=1\]
C) \[1/x+3/y=1\]
D) \[3x+y=1\]
Correct Answer: D
Solution :
Let the line be\[\frac{x}{a}+\frac{y}{b}=1,\]then \[\frac{1}{a}+\frac{3}{b}=1\] \[A=(a,0),B=(0,b)\] \[\Rightarrow \] \[P=(a,b)\] Thus, locus of p is\[\frac{1}{x}+\frac{3}{y}=1\]You need to login to perform this action.
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