A) \[H=\frac{2AG}{A+G}\]
B) \[A=H/{{G}^{2}}\]
C) \[H={{G}^{2}}/A\]
D) \[G={{H}^{2}}/A\]
Correct Answer: C
Solution :
\[A=\frac{a+b}{2},{{G}^{2}}=ab,H=\frac{2ab}{a+b}\] \[\therefore \] \[A\,H=\left( \frac{a+b}{2} \right)\left( \frac{2ab}{a+b} \right)\] \[ab={{G}^{2}}\] \[\Rightarrow \] \[H={{G}^{2}}/A\]You need to login to perform this action.
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