A) 4 s
B) 8 s
C) 10 s
D) 15 s
Correct Answer: B
Solution :
Let the minimum time after which the man catches the bus be t second. Then, For bus, \[s=ut+\frac{1}{2}a{{t}^{2}}\] i.e., \[{{s}_{b}}=(0)(t)+\frac{1}{2}(1){{(t)}^{2}}=\frac{{{t}^{2}}}{2}\] For man \[{{s}_{m}}=(10)(t)+\frac{1}{2}(0){{t}^{2}}=10t\] From the question\[{{s}_{m}}={{s}_{b}}+48\] \[\Rightarrow \] \[10t=\frac{{{t}^{2}}}{2}+48\] \[\Rightarrow \] \[{{t}^{2}}-20t+96=0\] \[\Rightarrow \] \[(t-8)(t-12)=0\] \[\therefore \] \[t=8\text{ }s\]You need to login to perform this action.
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