A) \[CI{{F}_{3}}\]
B) \[B{{F}_{3}}\]
C) \[Al{{F}_{3}}\]
D) \[N{{F}_{3}}\]
Correct Answer: A
Solution :
In\[CI{{F}_{3}}\]all bonds are not equal due to trigonal bypyramidal (\[s{{p}^{3}}d-\]hybridisation) geometry of\[Cl{{F}_{3}}\]molecule. \[B{{F}_{3}}\]and\[Al{{F}_{3}}\]show trigonal symmetric structure due to \[s{{p}^{2}}-\]hybridisation. \[N{{F}_{3}}\]shows pyramidal geometry due to\[s{{p}^{3}}\]hybridisationYou need to login to perform this action.
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