A) \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}\]
B) \[3{{x}^{2}}+3{{y}^{2}}=2{{a}^{2}}\]
C) \[9{{x}^{2}}+9{{y}^{2}}=4{{a}^{2}}\]
D) \[{{x}^{2}}+{{y}^{2}}=4{{a}^{2}}\]
Correct Answer: C
Solution :
Centre of triangle is (0, 0). \[\therefore \]Since, triangle is an equilateral, the centre of circumcircle is also (0, 0).You need to login to perform this action.
You will be redirected in
3 sec