RAJASTHAN ­ PET Rajasthan PET Solved Paper-2012

  • question_answer
    Two long straight wires are connected by a circular section that has a radius r as shown in figure. All segments of the wire lie in the same place and carry steady current I. The magnetic field at centre O of the circular segment will be

    A)  \[\frac{B{{\mu }_{0}}I}{4\pi r}\]

    B)  \[\frac{B{{\mu }_{0}}I}{r}\]

    C)  \[\frac{B{{\mu }_{0}}I}{2\pi r}\]

    D)  \[\frac{{{\mu }_{0}}I}{4\pi r}\]

    Correct Answer: A

    Solution :

     Since\[O\]lies on the extensions of straight conductors, therefore, magnetic field due to these segments is zero. Magnetic field due to circular segment \[=\frac{{{\mu }_{0}}I}{4\pi {{r}^{2}}}\times \](Length of circular segment) \[=\frac{{{\mu }_{0}}I}{4\pi {{r}^{2}}}\times \beta r\] \[=\frac{\beta {{\mu }_{0}}I}{4\pi r}\]


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