RAJASTHAN ­ PET Rajasthan PET Solved Paper-2012

  • question_answer
    End product of the following reaction is\[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow[red\,P]{C{{l}_{2}}}\xrightarrow[{}]{Alcoholic\text{ }KOH}\]

    A)  \[\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{C{{H}_{3}}CHCOO}}\,\]

    B)  \[\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{C{{H}_{2}}C{{H}_{2}}COO}}\,H\]

    C)  \[C{{H}_{2}}=CHCOOH\]

    D)  \[\underset{\begin{smallmatrix}  | \\  Cl \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,\underset{\begin{smallmatrix}  | \\  OH \end{smallmatrix}}{\mathop{CH}}\,COOH\]

    Correct Answer: C

    Solution :

     \[C{{H}_{3}}C{{H}_{2}}COOH\xrightarrow[(HVZ\text{ }reaction)]{C{{l}_{2}},red\,P}C{{H}_{3}}\underset{\begin{smallmatrix}  | \\  Cl \end{smallmatrix}}{\mathop{CH}}\,COOH\] \[\xrightarrow[(elimination)]{alcoholic\text{ }KOH}\underset{acrylic\,acid}{\mathop{C{{H}_{2}}=CHCOOH}}\,\]


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