A) \[-77.85{}^\circ C\]
B) \[+77.85{}^\circ C\]
C) \[-66.05{}^\circ C\]
D) None of these
Correct Answer: A
Solution :
Given,\[{{p}_{T}}=20.0\,kPa\]and\[p=14.3\text{ }kPa\] By the relation, \[T=(273.16K)\left( \frac{p}{{{p}_{T}}} \right)\] \[=(273.16K)\times \left( \frac{14.3kPa}{20.0kPa} \right)=195.3K\] On celsium scale \[\theta ({}^\circ C)=T(K)-273.15K\] \[=195.3-273.15\] \[=-77.83{}^\circ C\]You need to login to perform this action.
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