A) 2000 V volt
B) 20 V volt
C) V/2000 volt
D) \[\sqrt{2000}\]V volt
Correct Answer: C
Solution :
Energy of an accelerated particle is given as \[{{E}_{n}}=qV\] and wavelength, \[\lambda =\frac{h}{p}=\frac{h}{\sqrt{2mE}}=\frac{h}{\sqrt{2mqV}}\] Here, \[{{m}_{e}}{{V}_{e}}={{m}_{p}}{{V}_{p}}\] Or \[{{V}_{p}}=\frac{{{m}_{e}}{{V}_{e}}}{{{m}_{p}}}=V\times \frac{1}{2000}\] \[=\frac{V}{2000}volt\]You need to login to perform this action.
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