A) 3, 2, 1
B) 2, 4, 6
C) 1, 2, 3
D) 6, 4, 2
Correct Answer: A
Solution :
\[Xe\] | |
\[Xe\](First excited state which forms \[Xe{{F}_{2}})\] | |
\[Xe\](Second excited state which forms \[Xe{{F}_{4}})\] | |
\[Xe\](third excited state which forms \[Xe{{F}_{6}})\] |
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