A) \[0.186{}^\circ C\]
B) \[0.0512{}^\circ C\]
C) \[1.86{}^\circ C\]
D) \[5.12{}^\circ C\]
Correct Answer: B
Solution :
\[\Delta {{T}_{b}}=m{{K}_{b}}\] \[\Delta {{T}_{f}}=m{{K}_{f}}\] \[\frac{\Delta {{T}_{b}}}{\Delta {{T}_{f}}}=\frac{{{K}_{b}}}{{{K}_{f}}}=\frac{0.512}{1.86}\] \[\Delta {{T}_{b}}=\frac{0.512}{1.86}\times 0.186\] \[=0.0512{}^\circ C\]You need to login to perform this action.
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