A) elimination reaction
B) free radical substitution
C) nucleophilic substitution
D) elecrophilic substitution
Correct Answer: C
Solution :
\[{{(C{{H}_{3}})}_{3}}-CBr+{{H}_{2}}O\xrightarrow[{}]{{}}{{(C{{H}_{3}})}_{3}}-C-OH\] \[+HBr\] \[\because \]Br is substituted by\[-O{{H}^{-}}\](nucleophile). \[\therefore \] Reaction should be\[{{S}_{N}}1\](unimolecular substitution reaction).You need to login to perform this action.
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