A) \[4.9\,m/{{s}^{2}}\]
B) \[9.8\,m/{{s}^{2}}\]
C) \[19.6\,m/{{s}^{2}}\]
D) zero
Correct Answer: C
Solution :
At earth surface \[g=\frac{GM}{{{R}^{2}}}\] At planet \[g=\frac{GM/2}{{{(R/2)}^{2}}}=2\left( \frac{GM}{{{R}^{2}}} \right)\] \[=2\times 9.8=19.6m/{{s}^{2}}\]You need to login to perform this action.
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