A) more \[N{{H}_{4}}\] is formed
B) dissociation of \[N{{H}_{4}}Cl\]increase
C) more \[C{{l}^{-}}\] is formed
D) dissociation of \[N{{H}_{4}}Cl\]decreases
Correct Answer: D
Solution :
On addition of \[N{{H}_{4}}OH\] in the equilibrium \[N{{H}_{4}}ClN{{H}_{4}}^{+}+C{{l}^{-}}\] \[N{{H}_{4}}Cl\] reduces the ionization of \[N{{H}_{4}}OH\] due to the common ion effect.You need to login to perform this action.
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