A) \[2.5\,day\]
B) \[5\,day\]
C) \[10\,day\]
D) \[15\,day\]
Correct Answer: D
Solution :
Decayed quantity \[=\frac{7}{8}\] \[\therefore \] remaining quantity \[=1-\frac{7}{8}=\frac{1}{8}\] From \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}},\] \[{{N}_{0}}\] = initial amount, N =remaining amount \[\frac{{{N}_{0}}}{8}={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[{{\left( \frac{1}{2} \right)}^{3}}={{\left( \frac{1}{2} \right)}^{n}}\] n = number of half lives, \[n=3\] Time \[=n\times {{t}_{1/2}}=3\times 5=15\]day
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