A) \[2Q\]
B) \[4Q\]
C) \[16Q\]
D) \[32Q\]
Correct Answer: C
Solution :
Rate of emission of radiation is proportional to the 4th power of temperature. \[Q\propto {{T}^{4}}\] \[\frac{{{Q}_{1}}}{{{Q}_{2}}}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}\left( \frac{227+272}{727+273} \right)={{\left( \frac{500}{1000} \right)}^{4}}\] \[{{Q}_{2}}=16Q\]You need to login to perform this action.
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