A) 0.16 A
B) 0.32 A
C) 3.2 A
D) 1.6 A
Correct Answer: B
Solution :
Induced current \[I=\frac{A}{R}\,\,\,\frac{\Delta B}{\Delta t}\] \[=\frac{16\times {{10}^{-4}}}{2\times {{10}^{-3}}}\times \frac{0.4}{1}=0.32A\]You need to login to perform this action.
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