A) 1.53 H
B) 2.15 H
C) 3.27 H
D) 3.89 H
Correct Answer: A
Solution :
\[{{V}^{2}}={{V}_{R}}^{2}+B{{V}_{L}}^{2}\] \[V=\sqrt{{{V}^{2}}-{{V}_{R}}^{2}}=\sqrt{{{(100)}^{2}}-{{(60)}^{2}}}\] \[P=Vi\] \[10=60\times i=80volt\] \[i=\frac{1}{6}A\] \[{{X}_{L}}=\frac{V}{i}=\frac{80}{1/6}=480\Omega \] \[2\pi \,fL=480\] \[L=1.53H\]You need to login to perform this action.
You will be redirected in
3 sec