A) \[\frac{1}{2}\,{{i}_{0}}{{e}_{0}}\,watt\]
B) \[{{i}_{0}}{{e}_{0}}\] watt
C) \[ie\]watt
D) zero
Correct Answer: D
Solution :
\[i={{i}_{0}}\sin (\omega t\,-\pi /2),\,e={{e}_{0}}\sin \omega t\] Phase difference \[=\pi /2\] Average power loss \[={{i}_{rms}}\times {{e}_{rms}}\,\cos \phi \] \[={{i}_{rms}}\times {{e}_{rms}}\,\cos \,\pi /2=0\] \[\left\{ \cos \frac{\pi }{2}=0 \right\}\]You need to login to perform this action.
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