A) \[7.6\times {{10}^{-2}}\]
B) \[4.8\times {{10}^{-3}}\]
C) \[3.2\times {{10}^{-4}}\]
D) \[3.2\times {{10}^{-2}}\]
Correct Answer: A
Solution :
Magnetic field \[B=\frac{{{\mu }_{0}}ni}{l}\] \[=\frac{4\pi \times {{10}^{-7}}\times 2000\times 2}{0.3}\] Induced e.nr.f. \[E=-A\frac{B}{t}\] Substituting the values \[E=7.6\times {{10}^{-2}}\text{ }volt\]You need to login to perform this action.
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