A) \[+q\]
B) \[-q\]
C) \[+2q\]
D) \[3q\]
Correct Answer: B
Solution :
On charge Q, both 4q and q charge apply force. Net force of Q should be zero. \[K\frac{4q.\,\,q}{{{l}^{2}}}+\frac{K\,\,Q.q}{{{(1/2)}^{2}}}=0\] \[Q=-q\]You need to login to perform this action.
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