A) \[\frac{KE}{2r}\]
B) \[\frac{K{{E}^{2}}}{2r}\]
C) \[\frac{KE}{r}\]
D) \[\frac{2KE}{r}\]
Correct Answer: B
Solution :
Kinetic energy of an electron in orbit of radius \[r=\frac{K{{E}^{2}}}{2r}\] where \[K=\frac{Z}{4\pi {{\varepsilon }_{0}}}\]You need to login to perform this action.
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