A) \[8\,Hz\]
B) \[4\,Hz\]
C) \[6\,Hz\]
D) \[1\,Hz\]
Correct Answer: B
Solution :
Apparent frequency \[\Delta n=\frac{2{{\upsilon }_{0}}}{\upsilon }\times n\] Where \[{{\upsilon }_{0}}\] = speed of observer \[\upsilon \] = speed of sound. \[\Delta n=\frac{2\times 2}{330}\times 330\] n = frequency \[=4Hz\]You need to login to perform this action.
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