A) \[1:1\]
B) \[2:1\]
C) \[1:2\]
D) \[1:4\]
Correct Answer: D
Solution :
Remaing amount \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[{{N}_{1}}={{N}_{0}}{{\left( \frac{1}{2} \right)}^{48/12}},\] \[{{N}_{2}}=2{{N}_{0}}{{\left( \frac{1}{2} \right)}^{48/16}}\] \[=\frac{{{N}_{0}}}{4}=\frac{{{N}_{0}}}{16}\] \[{{N}_{1}}:{{N}_{2}}=1:4\]You need to login to perform this action.
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