A) \[{{[NiC{{l}_{4}}]}^{-2}}\]
B) \[{{[Ni{{(CN)}_{4}}]}^{-2}}\]
C) both (a) and (b)
D) none of these
Correct Answer: A
Solution :
\[{{[NiC{{l}_{4}}]}^{-2}}\]have unpaired electron. So that it is paramagnetic ion.
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