A) 125 m
B) 50 m
C) 100 m
D) 150 m
Correct Answer: A
Solution :
Using the equations of projectile flight time \[T=\frac{2u\,\sin \theta }{g}\] \[10=\frac{2u\,\,\sin \theta }{g}\] \[\Rightarrow \] \[u\,\sin \theta =5g\] Height \[h=\frac{{{u}^{2}}\,{{\sin }^{2}}\theta }{2g}=\frac{25{{g}^{2}}}{2g}=125m\]You need to login to perform this action.
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