A) propanal
B) propene
C) propane
D) ethanol
Correct Answer: A
Solution :
\[\underset{\text{Propanol}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH}}\,+{{H}_{2}}N.N{{H}_{2}}\xrightarrow{KOH}\] \[\underset{\text{Propanal}}{\mathop{C{{H}_{3}}C{{H}_{2}}CHO}}\,\]You need to login to perform this action.
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