A) half
B) one fourth
C) one third
D) no change
Correct Answer: B
Solution :
At earth surface \[g=\frac{GM}{{{R}^{2}}}\] At a height h from earth surface \[g=\frac{GM}{{{(R+h)}^{2}}}\] at \[h=R\,\,g=\frac{1}{4}\left( \frac{GM}{{{R}^{2}}} \right)\] \[\,g=\frac{g}{4}\] Weight will remainYou need to login to perform this action.
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