A) Wavelength is \[\pi \] meter
B) Frequency is \[\left( \frac{30}{\pi } \right)\]Hz
C) Velocity is 30 m/s
D) All of these
Correct Answer: B
Solution :
Equation of wave \[y={{10}^{-4}}\sin (60t+2x)\] Comparing this equation with \[y=a\sin (\omega t+kx)\] \[\omega =60\] \[n=\frac{\omega }{2\pi }=\frac{60}{2\pi }=\frac{30}{\pi }\] \[\therefore \] statement (b) is correct.You need to login to perform this action.
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