RAJASTHAN PMT Rajasthan - PMT Solved Paper-1999

  • question_answer
    Angular velocity of second hand of a clock is:

    A)  \[\frac{\pi }{30}rad/\sec \]     

    B)         \[\frac{\pi }{60}rad/\sec \]         

    C)         \[\frac{\pi }{15}rad/\sec \]     

    D)         \[\frac{\pi }{2}rad/\sec \]

    Correct Answer: A

    Solution :

    Second hand of a clock turns through an angle \[2\pi \] in 1 minute (= 60 sec) \[\therefore \]angular velocity \[\omega =\frac{2\pi }{60}=\frac{\pi }{30}\]rad/sec


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