A) \[S{{O}_{3}}\]
B) \[{{H}_{2}}S{{O}_{4}}\]
C) \[S{{O}_{4}}^{-\,\,-}\]
D) \[{{H}_{2}}S{{O}_{3}}\]
Correct Answer: D
Solution :
\[S{{O}_{3}}=x+3x-2=0\] \[x=+6\] \[{{H}_{2}}S{{O}_{4}}=2+x-8=0\] \[x=6\] \[S{{O}_{4}}^{-\,\,\,\,-}=x+(-8)=-2\] \[x-8=-2\] \[x=6\] \[{{H}_{2}}S{{O}_{4}}=2+x-6=0\] \[x=4\]You need to login to perform this action.
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