A) half of the initial value
B) double of initial value
C) one fourth of the initial value
D) same the initial value
Correct Answer: B
Solution :
As \[AB\] \[{{K}_{c}}=\frac{[B]}{[A]}\] Let concentration is double \[2A2B\] \[{{K}_{c}}=\frac{{{[B]}^{2}}}{{{[A]}^{2}}}\] Double of initial value.You need to login to perform this action.
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