A) ethylene
B) acetylene
C) ethane
D) ethyl alcohol
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{5}}Br\xrightarrow{alc.\,KOH}\underset{Acetylene}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\]You need to login to perform this action.
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