A) barbituric acid
B) methyl urea
C) semi carbide
D) acetamide
Correct Answer: C
Solution :
\[{{H}_{2}}N-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-N{{H}_{2}}+\underset{Hydrazine}{\mathop{H-NH-N{{H}_{2}}}}\,\xrightarrow{{}}\] \[\underset{Semi\,\,carbazide}{\mathop{{{H}_{2}}N-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-NH-N{{H}_{2}}+N{{H}_{3}}}}\,\]
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