A) \[\pi /3\]
B) \[\pi \]
C) \[\pi /2\]
D) zero
Correct Answer: C
Solution :
\[|\vec{a}+\vec{b}=\,|\vec{a}-\vec{b}|\] \[\therefore \] \[{{a}^{2}}+{{b}^{2}}+2|\vec{a}|\vec{b}|\,\cos \,\theta \] \[={{a}^{2}}+{{b}^{2}}-2\,|\vec{a}|\,|\vec{b}|\,\cos \theta \] On solving \[\theta =\frac{\pi }{2}\].You need to login to perform this action.
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