A) 2 : 1
B) 1 : 2
C) 4 : 1
D) 1 : 4
Correct Answer: B
Solution :
Momentum\[p\propto \sqrt{E}\] \[\frac{{{p}_{1}}}{{{P}_{2}}}=\frac{\sqrt{{{E}_{1}}}}{{{E}_{2}}}\] \[\therefore \] \[\sqrt{\frac{100}{400}}=\frac{10}{20}=1:2\]You need to login to perform this action.
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