A) \[2\mu F\]
B) \[3\mu F\]
C) \[4\mu F\]
D) \[0.5\mu F\]
Correct Answer: D
Solution :
Equivalent capacity of \[1\mu F\] and \[1\mu F\] capacitor joined in parallel \[C'=1+1=2\mu F\] Now, this circuit can be represented as Now, the total capacity of circuit in series \[\frac{1}{C}=\frac{1}{2}+\frac{1}{1}+\frac{1}{2}\] \[C=\frac{1}{2}=0.5\mu F\]You need to login to perform this action.
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