A) 50 metre
B) 100 metre
C) 200 metre
D) 400 metre
Correct Answer: C
Solution :
According to 2nd equation of motion \[\begin{align} & {{\upsilon }^{2}}={{u}^{2}}-2as \\ & 0={{u}^{2}}-2a\times 50 \\ \end{align}\] \[\Rightarrow \] \[a=\frac{{{u}^{2}}}{100}\] If initial velocity is doubled \[0={{(2u)}^{2}}-2as\] \[s=\frac{4{{u}^{2}}}{2a}=\frac{2{{u}^{2}}\times 100}{{{4}^{2}}}\] \[=200\,\text{meter}\]You need to login to perform this action.
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