A) 1 : 2
B) 1 : 4
C) 4 : 1
D) 2 : 1
Correct Answer: D
Solution :
Power\[p=\frac{{{V}^{2}}}{R}\] \[\therefore \] \[p\propto \frac{1}{R}\] \[\therefore \] \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{R}_{2}}}{{{R}_{2}}}=\frac{2}{1}\] \[{{P}_{1}}:{{P}_{2}}=2:1\]You need to login to perform this action.
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