RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    If each resistance in the figure is of 9\[\Omega \] then reading of ammeter is:           

    A)  5 A                        

    B)         8 A  

    C)  2 A                        

    D)         9 A

    Correct Answer: A

    Solution :

    Total resistance of circuit \[\frac{1}{R}=\frac{1}{9}+...9\] times \[\Rightarrow \,\,\,\,R=1\,\Omega \] \[i=\frac{V}{R}=\frac{9}{1}9\,\text{amp}\text{.}\] Current in each resistance is 9 amp. Reading of ammeter \[=1+1+1+1\,+1=5\,\text{amp}\]


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