A) 0.151 g
B) 0.32g
C) 0.51g
D) 0.16g
Correct Answer: B
Solution :
Remaining quantity \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{t/{{t}_{1/2}}}}\] \[N=10.38{{\left( \frac{1}{2} \right)}^{10/3.8}}\] \[=10.38{{\left( \frac{1}{2} \right)}^{5}}=\frac{10.38}{32}=0.32g\]You need to login to perform this action.
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