A) 0.5 mm
B) 0.25 mm
C) 0.05 mm
D) 5 mm
Correct Answer: C
Solution :
Youngs coefficient of elasticity \[Y=\frac{mgL}{\pi {{r}^{2}}\Delta L}\] substituting the values we get \[\Delta L=0.05\] mmYou need to login to perform this action.
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