RAJASTHAN PMT Rajasthan - PMT Solved Paper-2001

  • question_answer
    If the \[{{K}_{sp}}\] of \[AgCl\]is \[25\times {{10}^{-12}}\] at\[{{25}^{o}}C\]. Then solubility of \[AgCl\] is:

    A)  \[5\times {{10}^{-13}}\]

    B)  \[7.4\times {{10}^{-7}}\]

    C)  \[5\times {{10}^{-6}}\]       

    D)  \[2.5\times {{10}^{-6}}\]

    Correct Answer: C

    Solution :

    \[\underset{s}{\mathop{AgCl}}\,\underset{s}{\mathop{A{{g}^{+}}}}\,+C{{l}^{-}}\] \[{{K}_{sp}}={{s}^{2}}\] \[{{s}^{2}}={{K}_{sp}}\] \[s=\sqrt{{{K}_{sp}}}\] \[=\sqrt{25\times {{10}^{-12}}}=5\times {{10}^{-6}}\]


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