A) \[2\]
B) \[3\]
C) \[1/3\]
D) none of these
Correct Answer: C
Solution :
Equilibrium constant \[\frac{rate\text{ }constant\text{ }of\text{ }forward\text{ }reaction}{~rate\text{ }constant\text{ }of\text{ }backward\text{ }reaction}\] \[E{{q}^{m}}\] constant \[=\frac{2.5\times {{10}^{-4}}}{7.5\times {{10}^{-4}}}=\frac{1}{3}\]You need to login to perform this action.
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